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(a) V e3 for a cube. Since 1 ft So 1 ft3 1728 in3. (b) V e3 for a cube. Since 1 yd So 1 yd3 27ft3. (c) V e3 again. Since 1 dm3 So 1 liter 1000 cm3. 12 in, V 3 ft, V 10 cm3, V 123 33 103 1728 27 1000

(b) 0 ,

Finding volumes or cubes Find the volume V of a cube, in cubic feet, if one edge is (a) 4 in, (b) 4 ft, (c) 4 yd.

and, by current division, I2 R=2 sRC sC sRC 4 s2 RC 2 Vo I V 2=sC R=2 3 sRC 4 4 sRC 2 o 4 sRC 2

and C 40 mF, has two voltage sources in series with each other, v1 50 V and v2 100u t (V). Find (a) the capacitor voltage at t , (b) the time at which the capacitor voltage is zero and reversing polarity. Ans: a 13:2 V; b 55:5 ms Find the unit-impulse response of the circuit of Fig. 7-44; i.e., v2 for v1 t (a unit-area narrow voltage pulse). R 1 t= R1 C Ans: v2 2 t u t e R1 R1 C

To find the volume in cubic feet, we must express the side in feet. (a) V (b) V (c) V e3 and, since 4 in e3 43 64 ft3 12 ft, V 123 1728 ft3

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Equating the two expressions for I2 yields a Laplace-domain expression relating Vo and Vi : Vo or, after inverse transformation, vo 4 RC 2 vi dt dt 4 Vi s2 R2 C 2 1

Fig. 7-44 7.43 In the circuits of Fig. 7-45, RC 5 10 7 and v1 t 10 cos 1000t 3 cos 2000t . Find v2 t . Assume tan % when < 18. Ans: v2 t % 10 cos 1000 t 10 6 3 cos 2000 t 10 6 v1 t 10 6

1 3 ft,

The circuit of Fig. 9-22 is, in essence, a noninverting ampli er with a feedback impedance ZN and is known as a negative-impedance converter (NIC). Find the Thevenin or driving-point impedance to the right of the input terminals, and explain why such a name is appropriate.

Fig. 7-45

Finding the volumes of a rectangular solid, prism, and pyramid Find the volume of (a) A rectangular solid having a length of 6 in, a width of 4 in, and a height of 1 ft (b) A prism having a height of 15 yd and a triangular base of 120 ft2 (c) A pyramid having a height of 8 cm and a square base whose side is 41 cm 2

CHAP. 7]

iP _

6(4)(12) 120(45)

Fig. 2-22

1 9 2 3 2 (8)

Fig. 9-22

Fig. 2-23 (a) R 1 M ; (b) R 100 k ; (c) R 10 k . Hint: Compute the charge lost during the 1-ms period. Ans. (a) 0.1 V; (b) 1 V; (b) 10 V 2.26 The actual discharge current in Problem 2.25 is i 100=R e 10 t=R A. Find the capacitor voltage drop at 1 ms after connection to the resistor for (a) R 1 M ; (b) R 100 k ; (c) R 10 k . Ans. (a) 0.1 V; (b) 1 V; (c) 9.52 V A 10-mF capacitor discharges in an element such that its voltage is v 2e 1000t . delivered by the capacitor as functions of time. Ans. i 20e 1000t mA, p vi 40e 1000t mJ Find the current and power

Finding the volumes of a sphere, cylinder, and cone Find the volume of (a) A sphere with a radius of 10 in (b) A cylinder with a height of 4 yd and a base whose radius is 2 ft (c) A cone with a height of 2 ft and a base whose radius is 2 yd

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