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The lter Q is generally maintained below a value of 2. If we set Q = 2 and solve for Zo we obtain Zo = 2 1 2 3.24 = 1.62

thus proving eq. (9-A). Let us now make use of eq. (9-A) as follows. Recall that, in a purely resistive circuit, POWER can be calculated by the equation V 2 =R. Thus, for two voltages, V1 and V2 , applied to a resistance of R ohms, the POWER RATIO is P

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This widget is named after the buttons found in car radios back in the good ol days These mechanical arrays of buttons were designed so that each one, when pressed, would tune the radio to a particular station One of the key features of these radio buttons was that only one button could be depressed (in other words, be active) at a time When an inactive button was pressed, the currently active button would be undepressed, and functionally move to the inactive state The radio button widget works in much the same way; use it when you want the user to choose one and only one option from a list of options This widget is often associated with radio buttons It has a slightly different look and feel, and a different (albeit related) functionality Like a radio button, the check box widget presents the user with a list of options.

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Unlike the radio button widget, the check box widget allows the user to select as many or as few choices as she or he wants So, radio buttons are mutually exclusive, but check boxes are not This widget presents the user with a list of entries, set inside a rectangle that can have a scroll bar The entries are arranged in rows, one entry per row, so that the user can use a vertical scroll bar to search the list if there are more entries than can be displayed at one time The list widget allows the user to select as few or as many entries as she or he wants This widget is part text field, part list (a combo, get it ) When not selected, the combo box resembles a text field with a down arrow button appended to its right end.

and thus, substituting this value of P in eq. (315) then making use of eq. (9-A), eq. (315) becomes dB 20 log V1 =V2 10-A

The user can choose to key data into the field portion of the widget (like a text field), or choose the down arrow, which will cause a temporary list-like widget to appear The user can select an option from this.

If we use this impedance and the calculated resonant frequencies, we can de ne both inductors and both capacitors. L1 = C1 = L2 = C2 = 1.62 = 37 H 2 6895 1 = 14 F 2 6895 1.62 1.62 = 15 H 2 17, 237 1 = 5.7 F 2 17, 237 1.62

which, it should be noted, is true only if V1 and V2 are both applied to the same value of resistance of R ohms. Actually, however, in practice eq. (10-A) is often applied in cases where the two resistances are not equal; in such a case the results are not really in decibels but in what we could call logarithmic units.

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