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Find voltage v, current i, and energy W in the capacitor of Problem 2.27 at time t 0, 1, 3, 5, and 10 ms. By integrating the power delivered by the capacitor, show that the energy dissipated in the element during the interval from 0 to t is equal to the energy lost by the capacitor. Ans. t 0 1 ms 3 ms 5 ms 10 ms v 2V 736 mV 100 mV 13.5 mV 91 mV i 20 mA 7.36 mA 1 mA 135 mA 0.91 mA W 20 mJ 2.7 mJ 0.05 mJ % 0:001 mJ %0

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At the inverting node, the phasor input current is given by Ii IN so that Since Vd % 0; Vi Vo ZN (1)

4 3 3 pr 4 3 3 (3.14)10 2 3

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The current delivered by a current source is increased linearly from zero to 10 A in 1-ms time and then is decreased linearly back to zero in 2 ms. The source feeds a 3-k resistor in series with a 2-H inductor (see Fig. 2-24). (a) Find the energy dissipated in the resistor during the rise time W1 and the fall time W2 . (b) Find the energy delivered to the inductor during the above two intervals. (c) Find the energy delivered by the current source to the series RL combination during the preceding two intervals. Note: Series elements have the same current. The voltage drop across their combination is the sum of their individual voltages. Ans. a W1 100; W2 200; (b) W1 200; W2 200; (c) W1 300; W2 0, all in joules The voltage of a 5-mF capacitor is increased linearly from zero to 10 V in 1 ms time and is then kept at that level. Find the current. Find the total energy delivered to the capacitor and verify that delivered energy is equal to the energy stored in the capacitor. Ans. i 50 mA during 0 < t < 1 ms and is zero elsewhere, W 250 mJ.

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Observe that if ZP ZN , then the impedance Z appears to be converted to the negative of its value; hence the name. See Problem 9.16 for another example.

(3.14)(22)12

Fig. 2-24

1 2 3 (3.14)(6 )(2)

(a) Describe a circuit arrangement that makes use of the NIC of Problem 9.15 and Fig. 9-22, with only resistors and capacitors, to simulate a pure inductor. (b) If only four 10-k resistors and a 0.01- F capacitor are available for use in the circuit, determine the value of L that can be simulated.

A 10-mF capacitor is charged to 2 V A path is established between its terminals which draws a constant current of I0 (a) For I0 1 mA, how long does it take to reduce the capacitor voltage to 5 percent of its initial value (b) For what value of I0 does the capacitor voltage remain above 90 percent of its initial value after passage of 24 hours Ans (a) 19 ms, (b) 2315pA Energy gained (or lost) by an electric charge q traveling in an electric eld is qv, where v is the electric potential gained (or lost) In a capacitor with charge Q and terminal voltage V, let all charges go from one plate to the other By way of computation, show that the total energy W gained (or lost) is not QV but QV=2 and explain why.

Deriving formulas from V Bh From V Bh, the volume formula for a prism or cylinder, derive the volume formulas for the solids in Fig. 17-30.

Also note that QV=2 is equal to the initial energy content of the capacitor Ans W qvdt Q V 0 QV=2 1 CV 2 The apparent discrepancy is explained by the following 2 2 The starting voltage vetween the two plates is V As the charges migrate from one plate of the capacitor to the other plate, the voltage between the two plates drops and becomes zero when all charges have moved The average of the voltage during the migration process is V=2, and therefore, the total energy is QV=2 Lightning I The time pro le of the discharge current in a typical cloud-to-ground lightning stroke is modeled by a triangle The surge takes 1 ms to reach the peak value of 100 kA and then is reduced to zero in 99 mS (a) Find the electric charge Q discharged.

(a) Consider the circuit of Fig. 9-23.

Fig. 17-30

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